(b^2-b-42)/(3b^2-108)

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Solution for (b^2-b-42)/(3b^2-108) equation: 


D( b )

3*b^2-108 = 0

3*b^2-108 = 0

3*b^2-108 = 0

3*b^2 = 108 // : 3

b^2 = 36

b^2 = 36 // ^ 1/2

abs(b) = 6

b = 6 or b = -6

b in (-oo:-6) U (-6:6) U (6:+oo)

(b^2-b-42)/(3*b^2-108) = 0

b^2-b-42 = 0

b^2-b-42 = 0

DELTA = (-1)^2-(-42*1*4)

DELTA = 169

DELTA > 0

b = (169^(1/2)+1)/(1*2) or b = (1-169^(1/2))/(1*2)

b = 7 or b = -6

(b+6)*(b-7) = 0

((b+6)*(b-7))/(3*b^2-108) = 0

( b+6 )

b+6 = 0 // - 6

b = -6

( b-7 )

b-7 = 0 // + 7

b = 7

b in { -6} 

b = 7

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